All to "pot"!!

[dingdong]

Hi to all,recently I posted a thread on the  recovery of what I now know to be a piece of an old iron pot!!
Thought that now I am over the disappointment (LOL) and that it was only "a bit-a-pot" and carting it back in my rucksack for a mile,feeling totally kna*****D i feel it is only right to show a couple a photographs of the said pot.
The actual size is approximately nine and a half inches tall,X nine inches deep,the curvature with a straight edge put across the inside is about an inch and a quarter,the question is....has any of you "maths" boffins be able to come up with an approximation of its original size...PLEASE.
Also,the thickness  of the walls is about a quarter of an inch thick !!
........Second..bit....Now,not suggesting that it is,but,does any one know if they did ritual cremations,did they use iron pots,or clay pots!!
I look forward to hearing all your comments, many thanks for looking👍

[Val Beechey]

Wiki article, link below, says clay or bronze pots were used. 

https://en.wikipedia.org/wiki/Cremation

[Chef Geoff]

Difficult to judge the size from the fragment but continuing the form around may give you about a 12" diameter (37" circumference) and roughly 12" high which taking in to account that it tapers would probably give you a 4 gallon pot

[dingdong]

Weyhey!!!!Chef,big thanks for that,those dimensions make it a pretty hefty old pot,tell you what though,trying to extracate even that piece b******D me up!!anyway,thanks once again !👍

[Cymro]

Okay, we know the chord length (9") and the sagitta length (1.25")

The formula for finding the radius of the curve is;

r=(s^2 + L^2) / 2S where S= sagitta length and L = half the chord length.

Plugging the numbers into the formula gives:

r = (1.25^2 + 4.5^2) / (2 x 1.25)

r = (1.5625 + 20.25) / 2.5

r = 21.8125 / 2.5

r = 8.725

Since the diameter is twice the radius, it's a 17.45" pot on the inside. Anybody care to correct me?

Any sign of witches around there . . . ? 

[Val Beechey]

Well, there's always me   

[Cymro]

Well, there's always me   

Surely not . . .

[dingdong]

Must be the heat.......now were all goin "POTTY".   !!!!
But Cymru, your calculus using " sagitus" is actually spot on !!well done!!👏👏👏📐👍

[Cymro]

But Cymru, your calculus using " sagitus" is actually spot on !!well done!!👏👏👏📐👍

That calculus is geometry. The solution is based on Pythagoras' Theorem . . . 

[dingdong]

Yes,now I know!!! I thought it was a fictitious calculous !!that was until I googled it,woops,talk about egg on my face!!...LOL
You clever lad!!👏👏👏👏👏👏📐📐👍

[Cymro]

Weren't nuthin really . . .

I spent donkeys years in engineering - it's the kind of thing it's handy to know from time to time . . .  

[dingdong]

Hey old buddy,as I said previously, "clever old you .👍