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Metal Detecting Discussions => Metal Detector Finds => Topic started by: dingdong on June 30, 2015, 05:04:00 PM



Title: All to "pot"!!
Post by: dingdong on June 30, 2015, 05:04:00 PM
Hi to all,recently I posted a thread on the  recovery of what I now know to be a piece of an old iron pot!!
Thought that now I am over the disappointment (LOL) and that it was only "a bit-a-pot" and carting it back in my rucksack for a mile,feeling totally kna*****D i feel it is only right to show a couple a photographs of the said pot.
The actual size is approximately nine and a half inches tall,X nine inches deep,the curvature with a straight edge put across the inside is about an inch and a quarter,the question is....has any of you "maths" boffins be able to come up with an approximation of its original size...PLEASE.
Also,the thickness  of the walls is about a quarter of an inch thick !!
........Second..bit....Now,not suggesting that it is,but,does any one know if they did ritual cremations,did they use iron pots,or clay pots!!
I look forward to hearing all your comments, many thanks for looking👍



Title: Re: All to "pot"!!
Post by: Val Beechey on June 30, 2015, 05:28:41 PM
Wiki article, link below, says clay or bronze pots were used. 

https://en.wikipedia.org/wiki/Cremation


Title: Re: All to "pot"!!
Post by: Chef Geoff on June 30, 2015, 06:41:14 PM
Difficult to judge the size from the fragment but continuing the form around may give you about a 12" diameter (37" circumference) and roughly 12" high which taking in to account that it tapers would probably give you a 4 gallon pot ???


Title: Re: All to "pot"!!
Post by: dingdong on June 30, 2015, 07:28:16 PM
Weyhey!!!!Chef,big thanks for that,those dimensions make it a pretty hefty old pot,tell you what though,trying to extracate even that piece b******D me up!!anyway,thanks once again !👍


Title: Re: All to "pot"!!
Post by: Cymro on July 01, 2015, 10:27:48 AM
Okay, we know the chord length (9") and the sagitta length (1.25")

The formula for finding the radius of the curve is;

r=(s^2 + L^2) / 2S where S= sagitta length and L = half the chord length.

Plugging the numbers into the formula gives:

r = (1.25^2 + 4.5^2) / (2 x 1.25)

r = (1.5625 + 20.25) / 2.5

r = 21.8125 / 2.5

r = 8.725

Since the diameter is twice the radius, it's a 17.45" pot on the inside. Anybody care to correct me?

Any sign of witches around there . . . ?  ;)




Title: Re: All to "pot"!!
Post by: Val Beechey on July 01, 2015, 01:06:11 PM
Well, there's always me    ;D ::)


Title: Re: All to "pot"!!
Post by: Cymro on July 01, 2015, 01:16:54 PM
Well, there's always me    ;D ::)

Surely not . . .


Title: Re: All to "pot"!!
Post by: dingdong on July 01, 2015, 04:48:10 PM
Must be the heat.......now were all goin "POTTY".   !!!!
But Cymru, your calculus using " sagitus" is actually spot on !!well done!!👏👏👏📐👍


Title: Re: All to "pot"!!
Post by: Cymro on July 01, 2015, 07:01:06 PM

But Cymru, your calculus using " sagitus" is actually spot on !!well done!!👏👏👏📐👍


That calculus is geometry. The solution is based on Pythagoras' Theorem . . .  ;)


Title: Re: All to "pot"!!
Post by: dingdong on July 01, 2015, 07:54:14 PM
Yes,now I know!!! I thought it was a fictitious calculous !!that was until I googled it,woops,talk about egg on my face!!...LOL
You clever lad!!👏👏👏👏👏👏📐📐👍


Title: Re: All to "pot"!!
Post by: Cymro on July 02, 2015, 08:55:25 AM
Weren't nuthin really . . .

I spent donkeys years in engineering - it's the kind of thing it's handy to know from time to time . . .  ;)


Title: Re: All to "pot"!!
Post by: dingdong on July 02, 2015, 05:49:45 PM
Hey old buddy,as I said previously, "clever old you .👍


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