Title: All to "pot"!! Post by: dingdong on June 30, 2015, 05:04:00 PM Hi to all,recently I posted a thread on the recovery of what I now know to be a piece of an old iron pot!!
Thought that now I am over the disappointment (LOL) and that it was only "a bit-a-pot" and carting it back in my rucksack for a mile,feeling totally kna*****D i feel it is only right to show a couple a photographs of the said pot. The actual size is approximately nine and a half inches tall,X nine inches deep,the curvature with a straight edge put across the inside is about an inch and a quarter,the question is....has any of you "maths" boffins be able to come up with an approximation of its original size...PLEASE. Also,the thickness of the walls is about a quarter of an inch thick !! ........Second..bit....Now,not suggesting that it is,but,does any one know if they did ritual cremations,did they use iron pots,or clay pots!! I look forward to hearing all your comments, many thanks for looking👍 Title: Re: All to "pot"!! Post by: Val Beechey on June 30, 2015, 05:28:41 PM Wiki article, link below, says clay or bronze pots were used.
https://en.wikipedia.org/wiki/Cremation Title: Re: All to "pot"!! Post by: Chef Geoff on June 30, 2015, 06:41:14 PM Difficult to judge the size from the fragment but continuing the form around may give you about a 12" diameter (37" circumference) and roughly 12" high which taking in to account that it tapers would probably give you a 4 gallon pot ???
Title: Re: All to "pot"!! Post by: dingdong on June 30, 2015, 07:28:16 PM Weyhey!!!!Chef,big thanks for that,those dimensions make it a pretty hefty old pot,tell you what though,trying to extracate even that piece b******D me up!!anyway,thanks once again !👍
Title: Re: All to "pot"!! Post by: Cymro on July 01, 2015, 10:27:48 AM Okay, we know the chord length (9") and the sagitta length (1.25")
The formula for finding the radius of the curve is; r=(s^2 + L^2) / 2S where S= sagitta length and L = half the chord length. Plugging the numbers into the formula gives: r = (1.25^2 + 4.5^2) / (2 x 1.25) r = (1.5625 + 20.25) / 2.5 r = 21.8125 / 2.5 r = 8.725 Since the diameter is twice the radius, it's a 17.45" pot on the inside. Anybody care to correct me? Any sign of witches around there . . . ? ;) Title: Re: All to "pot"!! Post by: Val Beechey on July 01, 2015, 01:06:11 PM Well, there's always me ;D ::)
Title: Re: All to "pot"!! Post by: Cymro on July 01, 2015, 01:16:54 PM Title: Re: All to "pot"!! Post by: dingdong on July 01, 2015, 04:48:10 PM Must be the heat.......now were all goin "POTTY". !!!!
But Cymru, your calculus using " sagitus" is actually spot on !!well done!!👏👏👏📐👍 Title: Re: All to "pot"!! Post by: Cymro on July 01, 2015, 07:01:06 PM But Cymru, your calculus using " sagitus" is actually spot on !!well done!!👏👏👏📐👍 That calculus is geometry. The solution is based on Pythagoras' Theorem . . . ;) Title: Re: All to "pot"!! Post by: dingdong on July 01, 2015, 07:54:14 PM Yes,now I know!!! I thought it was a fictitious calculous !!that was until I googled it,woops,talk about egg on my face!!...LOL
You clever lad!!👏👏👏👏👏👏📐📐👍 Title: Re: All to "pot"!! Post by: Cymro on July 02, 2015, 08:55:25 AM Weren't nuthin really . . .
I spent donkeys years in engineering - it's the kind of thing it's handy to know from time to time . . . ;) Title: Re: All to "pot"!! Post by: dingdong on July 02, 2015, 05:49:45 PM Hey old buddy,as I said previously, "clever old you .👍
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